(25n^2-55n+24)=0

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Solution for (25n^2-55n+24)=0 equation:



(25n^2-55n+24)=0
We get rid of parentheses
25n^2-55n+24=0
a = 25; b = -55; c = +24;
Δ = b2-4ac
Δ = -552-4·25·24
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-25}{2*25}=\frac{30}{50} =3/5 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+25}{2*25}=\frac{80}{50} =1+3/5 $

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